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-6c^2+5c+6=0
a = -6; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·(-6)·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-13}{2*-6}=\frac{-18}{-12} =1+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+13}{2*-6}=\frac{8}{-12} =-2/3 $
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